3.2.47 \(\int \frac {A+C x^2}{(a+b x+c x^2)^4} \, dx\) [147]

3.2.47.1 Optimal result
3.2.47.2 Mathematica [A] (verified)
3.2.47.3 Rubi [A] (verified)
3.2.47.4 Maple [B] (verified)
3.2.47.5 Fricas [B] (verification not implemented)
3.2.47.6 Sympy [B] (verification not implemented)
3.2.47.7 Maxima [F(-2)]
3.2.47.8 Giac [B] (verification not implemented)
3.2.47.9 Mupad [B] (verification not implemented)

3.2.47.1 Optimal result

Integrand size = 20, antiderivative size = 206 \[ \int \frac {A+C x^2}{\left (a+b x+c x^2\right )^4} \, dx=-\frac {b c \left (A+\frac {a C}{c}\right )+\left (2 A c^2+\left (b^2-2 a c\right ) C\right ) x}{3 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^3}+\frac {\left (5 A c+\left (a+\frac {b^2}{c}\right ) C\right ) (b+2 c x)}{3 \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )^2}-\frac {2 \left (5 A c^2+\left (b^2+a c\right ) C\right ) (b+2 c x)}{\left (b^2-4 a c\right )^3 \left (a+b x+c x^2\right )}+\frac {8 c \left (5 A c^2+\left (b^2+a c\right ) C\right ) \text {arctanh}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c\right )^{7/2}} \]

output
1/3*(-b*c*(A+a*C/c)-(2*A*c^2+(-2*a*c+b^2)*C)*x)/c/(-4*a*c+b^2)/(c*x^2+b*x+ 
a)^3+1/3*(5*A*c+(a+b^2/c)*C)*(2*c*x+b)/(-4*a*c+b^2)^2/(c*x^2+b*x+a)^2-2*(5 
*A*c^2+(a*c+b^2)*C)*(2*c*x+b)/(-4*a*c+b^2)^3/(c*x^2+b*x+a)+8*c*(5*A*c^2+(a 
*c+b^2)*C)*arctanh((2*c*x+b)/(-4*a*c+b^2)^(1/2))/(-4*a*c+b^2)^(7/2)
 
3.2.47.2 Mathematica [A] (verified)

Time = 0.22 (sec) , antiderivative size = 204, normalized size of antiderivative = 0.99 \[ \int \frac {A+C x^2}{\left (a+b x+c x^2\right )^4} \, dx=\frac {1}{3} \left (\frac {\left (5 A c^2+\left (b^2+a c\right ) C\right ) (b+2 c x)}{c \left (b^2-4 a c\right )^2 (a+x (b+c x))^2}-\frac {6 \left (5 A c^2+\left (b^2+a c\right ) C\right ) (b+2 c x)}{\left (b^2-4 a c\right )^3 (a+x (b+c x))}+\frac {b^2 C x+a C (b-2 c x)+A c (b+2 c x)}{c \left (-b^2+4 a c\right ) (a+x (b+c x))^3}+\frac {24 c \left (5 A c^2+\left (b^2+a c\right ) C\right ) \arctan \left (\frac {b+2 c x}{\sqrt {-b^2+4 a c}}\right )}{\left (-b^2+4 a c\right )^{7/2}}\right ) \]

input
Integrate[(A + C*x^2)/(a + b*x + c*x^2)^4,x]
 
output
(((5*A*c^2 + (b^2 + a*c)*C)*(b + 2*c*x))/(c*(b^2 - 4*a*c)^2*(a + x*(b + c* 
x))^2) - (6*(5*A*c^2 + (b^2 + a*c)*C)*(b + 2*c*x))/((b^2 - 4*a*c)^3*(a + x 
*(b + c*x))) + (b^2*C*x + a*C*(b - 2*c*x) + A*c*(b + 2*c*x))/(c*(-b^2 + 4* 
a*c)*(a + x*(b + c*x))^3) + (24*c*(5*A*c^2 + (b^2 + a*c)*C)*ArcTan[(b + 2* 
c*x)/Sqrt[-b^2 + 4*a*c]])/(-b^2 + 4*a*c)^(7/2))/3
 
3.2.47.3 Rubi [A] (verified)

Time = 0.35 (sec) , antiderivative size = 203, normalized size of antiderivative = 0.99, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {2191, 27, 1086, 1086, 1083, 219}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {A+C x^2}{\left (a+b x+c x^2\right )^4} \, dx\)

\(\Big \downarrow \) 2191

\(\displaystyle -\frac {\int \frac {2 \left (5 A c+\left (\frac {b^2}{c}+a\right ) C\right )}{\left (c x^2+b x+a\right )^3}dx}{3 \left (b^2-4 a c\right )}-\frac {x \left (C \left (b^2-2 a c\right )+2 A c^2\right )+b c \left (\frac {a C}{c}+A\right )}{3 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^3}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {2 \left (C \left (a+\frac {b^2}{c}\right )+5 A c\right ) \int \frac {1}{\left (c x^2+b x+a\right )^3}dx}{3 \left (b^2-4 a c\right )}-\frac {x \left (C \left (b^2-2 a c\right )+2 A c^2\right )+b c \left (\frac {a C}{c}+A\right )}{3 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^3}\)

\(\Big \downarrow \) 1086

\(\displaystyle -\frac {2 \left (C \left (a+\frac {b^2}{c}\right )+5 A c\right ) \left (-\frac {3 c \int \frac {1}{\left (c x^2+b x+a\right )^2}dx}{b^2-4 a c}-\frac {b+2 c x}{2 \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^2}\right )}{3 \left (b^2-4 a c\right )}-\frac {x \left (C \left (b^2-2 a c\right )+2 A c^2\right )+b c \left (\frac {a C}{c}+A\right )}{3 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^3}\)

\(\Big \downarrow \) 1086

\(\displaystyle -\frac {2 \left (C \left (a+\frac {b^2}{c}\right )+5 A c\right ) \left (-\frac {3 c \left (-\frac {2 c \int \frac {1}{c x^2+b x+a}dx}{b^2-4 a c}-\frac {b+2 c x}{\left (b^2-4 a c\right ) \left (a+b x+c x^2\right )}\right )}{b^2-4 a c}-\frac {b+2 c x}{2 \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^2}\right )}{3 \left (b^2-4 a c\right )}-\frac {x \left (C \left (b^2-2 a c\right )+2 A c^2\right )+b c \left (\frac {a C}{c}+A\right )}{3 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^3}\)

\(\Big \downarrow \) 1083

\(\displaystyle -\frac {2 \left (C \left (a+\frac {b^2}{c}\right )+5 A c\right ) \left (-\frac {3 c \left (\frac {4 c \int \frac {1}{b^2-(b+2 c x)^2-4 a c}d(b+2 c x)}{b^2-4 a c}-\frac {b+2 c x}{\left (b^2-4 a c\right ) \left (a+b x+c x^2\right )}\right )}{b^2-4 a c}-\frac {b+2 c x}{2 \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^2}\right )}{3 \left (b^2-4 a c\right )}-\frac {x \left (C \left (b^2-2 a c\right )+2 A c^2\right )+b c \left (\frac {a C}{c}+A\right )}{3 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^3}\)

\(\Big \downarrow \) 219

\(\displaystyle -\frac {2 \left (C \left (a+\frac {b^2}{c}\right )+5 A c\right ) \left (-\frac {3 c \left (\frac {4 c \text {arctanh}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c\right )^{3/2}}-\frac {b+2 c x}{\left (b^2-4 a c\right ) \left (a+b x+c x^2\right )}\right )}{b^2-4 a c}-\frac {b+2 c x}{2 \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^2}\right )}{3 \left (b^2-4 a c\right )}-\frac {x \left (C \left (b^2-2 a c\right )+2 A c^2\right )+b c \left (\frac {a C}{c}+A\right )}{3 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^3}\)

input
Int[(A + C*x^2)/(a + b*x + c*x^2)^4,x]
 
output
-1/3*(b*c*(A + (a*C)/c) + (2*A*c^2 + (b^2 - 2*a*c)*C)*x)/(c*(b^2 - 4*a*c)* 
(a + b*x + c*x^2)^3) - (2*(5*A*c + (a + b^2/c)*C)*(-1/2*(b + 2*c*x)/((b^2 
- 4*a*c)*(a + b*x + c*x^2)^2) - (3*c*(-((b + 2*c*x)/((b^2 - 4*a*c)*(a + b* 
x + c*x^2))) + (4*c*ArcTanh[(b + 2*c*x)/Sqrt[b^2 - 4*a*c]])/(b^2 - 4*a*c)^ 
(3/2)))/(b^2 - 4*a*c)))/(3*(b^2 - 4*a*c))
 

3.2.47.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 219
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* 
ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt 
Q[a, 0] || LtQ[b, 0])
 

rule 1083
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Simp[-2   Subst[I 
nt[1/Simp[b^2 - 4*a*c - x^2, x], x], x, b + 2*c*x], x] /; FreeQ[{a, b, c}, 
x]
 

rule 1086
Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(b + 2*c*x) 
*((a + b*x + c*x^2)^(p + 1)/((p + 1)*(b^2 - 4*a*c))), x] - Simp[2*c*((2*p + 
 3)/((p + 1)*(b^2 - 4*a*c)))   Int[(a + b*x + c*x^2)^(p + 1), x], x] /; Fre 
eQ[{a, b, c}, x] && ILtQ[p, -1]
 

rule 2191
Int[(Pq_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> With[{Q = 
PolynomialQuotient[Pq, a + b*x + c*x^2, x], f = Coeff[PolynomialRemainder[P 
q, a + b*x + c*x^2, x], x, 0], g = Coeff[PolynomialRemainder[Pq, a + b*x + 
c*x^2, x], x, 1]}, Simp[(b*f - 2*a*g + (2*c*f - b*g)*x)*((a + b*x + c*x^2)^ 
(p + 1)/((p + 1)*(b^2 - 4*a*c))), x] + Simp[1/((p + 1)*(b^2 - 4*a*c))   Int 
[(a + b*x + c*x^2)^(p + 1)*ExpandToSum[(p + 1)*(b^2 - 4*a*c)*Q - (2*p + 3)* 
(2*c*f - b*g), x], x], x]] /; FreeQ[{a, b, c}, x] && PolyQ[Pq, x] && NeQ[b^ 
2 - 4*a*c, 0] && LtQ[p, -1]
 
3.2.47.4 Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(509\) vs. \(2(200)=400\).

Time = 0.65 (sec) , antiderivative size = 510, normalized size of antiderivative = 2.48

method result size
default \(\frac {\frac {4 c^{3} \left (5 A \,c^{2}+C a c +C \,b^{2}\right ) x^{5}}{64 a^{3} c^{3}-48 a^{2} b^{2} c^{2}+12 a \,b^{4} c -b^{6}}+\frac {10 c^{2} \left (5 A \,c^{2}+C a c +C \,b^{2}\right ) b \,x^{4}}{64 a^{3} c^{3}-48 a^{2} b^{2} c^{2}+12 a \,b^{4} c -b^{6}}+\frac {2 \left (16 a c +11 b^{2}\right ) c \left (5 A \,c^{2}+C a c +C \,b^{2}\right ) x^{3}}{3 \left (64 a^{3} c^{3}-48 a^{2} b^{2} c^{2}+12 a \,b^{4} c -b^{6}\right )}+\frac {b \left (16 a c +b^{2}\right ) \left (5 A \,c^{2}+C a c +C \,b^{2}\right ) x^{2}}{64 a^{3} c^{3}-48 a^{2} b^{2} c^{2}+12 a \,b^{4} c -b^{6}}+\frac {\left (44 A \,a^{2} c^{3}+18 A a \,b^{2} c^{2}-A \,b^{4} c -4 C \,a^{3} c^{2}+22 C \,a^{2} b^{2} c +C a \,b^{4}\right ) x}{64 a^{3} c^{3}-48 a^{2} b^{2} c^{2}+12 a \,b^{4} c -b^{6}}+\frac {\left (66 A \,a^{2} c^{2}-13 A a \,b^{2} c +A \,b^{4}+26 C \,a^{3} c +C \,a^{2} b^{2}\right ) b}{192 a^{3} c^{3}-144 a^{2} b^{2} c^{2}+36 a \,b^{4} c -3 b^{6}}}{\left (c \,x^{2}+b x +a \right )^{3}}+\frac {8 c \left (5 A \,c^{2}+C a c +C \,b^{2}\right ) \arctan \left (\frac {2 c x +b}{\sqrt {4 a c -b^{2}}}\right )}{\left (64 a^{3} c^{3}-48 a^{2} b^{2} c^{2}+12 a \,b^{4} c -b^{6}\right ) \sqrt {4 a c -b^{2}}}\) \(510\)
risch \(\text {Expression too large to display}\) \(1005\)

input
int((C*x^2+A)/(c*x^2+b*x+a)^4,x,method=_RETURNVERBOSE)
 
output
(4*c^3*(5*A*c^2+C*a*c+C*b^2)/(64*a^3*c^3-48*a^2*b^2*c^2+12*a*b^4*c-b^6)*x^ 
5+10*c^2*(5*A*c^2+C*a*c+C*b^2)/(64*a^3*c^3-48*a^2*b^2*c^2+12*a*b^4*c-b^6)* 
b*x^4+2/3*(16*a*c+11*b^2)*c*(5*A*c^2+C*a*c+C*b^2)/(64*a^3*c^3-48*a^2*b^2*c 
^2+12*a*b^4*c-b^6)*x^3+b*(16*a*c+b^2)*(5*A*c^2+C*a*c+C*b^2)/(64*a^3*c^3-48 
*a^2*b^2*c^2+12*a*b^4*c-b^6)*x^2+(44*A*a^2*c^3+18*A*a*b^2*c^2-A*b^4*c-4*C* 
a^3*c^2+22*C*a^2*b^2*c+C*a*b^4)/(64*a^3*c^3-48*a^2*b^2*c^2+12*a*b^4*c-b^6) 
*x+1/3*(66*A*a^2*c^2-13*A*a*b^2*c+A*b^4+26*C*a^3*c+C*a^2*b^2)*b/(64*a^3*c^ 
3-48*a^2*b^2*c^2+12*a*b^4*c-b^6))/(c*x^2+b*x+a)^3+8*c*(5*A*c^2+C*a*c+C*b^2 
)/(64*a^3*c^3-48*a^2*b^2*c^2+12*a*b^4*c-b^6)/(4*a*c-b^2)^(1/2)*arctan((2*c 
*x+b)/(4*a*c-b^2)^(1/2))
 
3.2.47.5 Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 1041 vs. \(2 (198) = 396\).

Time = 0.32 (sec) , antiderivative size = 2103, normalized size of antiderivative = 10.21 \[ \int \frac {A+C x^2}{\left (a+b x+c x^2\right )^4} \, dx=\text {Too large to display} \]

input
integrate((C*x^2+A)/(c*x^2+b*x+a)^4,x, algorithm="fricas")
 
output
[-1/3*(C*a^2*b^5 + A*b^7 - 264*A*a^3*b*c^3 + 12*(C*b^4*c^3 - 3*C*a*b^2*c^4 
 - 20*A*a*c^6 - (4*C*a^2 - 5*A*b^2)*c^5)*x^5 + 30*(C*b^5*c^2 - 3*C*a*b^3*c 
^3 - 20*A*a*b*c^5 - (4*C*a^2*b - 5*A*b^3)*c^4)*x^4 + 2*(11*C*b^6*c - 17*C* 
a*b^4*c^2 - 320*A*a^2*c^5 - 4*(16*C*a^3 + 35*A*a*b^2)*c^4 - (92*C*a^2*b^2 
- 55*A*b^4)*c^3)*x^3 - 2*(52*C*a^4*b - 59*A*a^2*b^3)*c^2 + 3*(C*b^7 + 13*C 
*a*b^5*c - 320*A*a^2*b*c^4 - 4*(16*C*a^3*b - 15*A*a*b^3)*c^3 - (52*C*a^2*b 
^3 - 5*A*b^5)*c^2)*x^2 + 12*(C*a^3*b^2*c + C*a^4*c^2 + 5*A*a^3*c^3 + (C*b^ 
2*c^4 + C*a*c^5 + 5*A*c^6)*x^6 + 3*(C*b^3*c^3 + C*a*b*c^4 + 5*A*b*c^5)*x^5 
 + 3*(C*b^4*c^2 + 2*C*a*b^2*c^3 + 5*A*a*c^5 + (C*a^2 + 5*A*b^2)*c^4)*x^4 + 
 (C*b^5*c + 7*C*a*b^3*c^2 + 30*A*a*b*c^4 + (6*C*a^2*b + 5*A*b^3)*c^3)*x^3 
+ 3*(C*a*b^4*c + 2*C*a^2*b^2*c^2 + 5*A*a^2*c^4 + (C*a^3 + 5*A*a*b^2)*c^3)* 
x^2 + 3*(C*a^2*b^3*c + C*a^3*b*c^2 + 5*A*a^2*b*c^3)*x)*sqrt(b^2 - 4*a*c)*l 
og((2*c^2*x^2 + 2*b*c*x + b^2 - 2*a*c - sqrt(b^2 - 4*a*c)*(2*c*x + b))/(c* 
x^2 + b*x + a)) + (22*C*a^3*b^3 - 17*A*a*b^5)*c + 3*(C*a*b^6 - 176*A*a^3*c 
^4 + 4*(4*C*a^4 - 7*A*a^2*b^2)*c^3 - 2*(46*C*a^3*b^2 - 11*A*a*b^4)*c^2 + ( 
18*C*a^2*b^4 - A*b^6)*c)*x)/(a^3*b^8 - 16*a^4*b^6*c + 96*a^5*b^4*c^2 - 256 
*a^6*b^2*c^3 + 256*a^7*c^4 + (b^8*c^3 - 16*a*b^6*c^4 + 96*a^2*b^4*c^5 - 25 
6*a^3*b^2*c^6 + 256*a^4*c^7)*x^6 + 3*(b^9*c^2 - 16*a*b^7*c^3 + 96*a^2*b^5* 
c^4 - 256*a^3*b^3*c^5 + 256*a^4*b*c^6)*x^5 + 3*(b^10*c - 15*a*b^8*c^2 + 80 
*a^2*b^6*c^3 - 160*a^3*b^4*c^4 + 256*a^5*c^6)*x^4 + (b^11 - 10*a*b^9*c ...
 
3.2.47.6 Sympy [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 1224 vs. \(2 (196) = 392\).

Time = 1.99 (sec) , antiderivative size = 1224, normalized size of antiderivative = 5.94 \[ \int \frac {A+C x^2}{\left (a+b x+c x^2\right )^4} \, dx=- 4 c \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{7}}} \cdot \left (5 A c^{2} + C a c + C b^{2}\right ) \log {\left (x + \frac {20 A b c^{3} + 4 C a b c^{2} + 4 C b^{3} c - 1024 a^{4} c^{5} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{7}}} \cdot \left (5 A c^{2} + C a c + C b^{2}\right ) + 1024 a^{3} b^{2} c^{4} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{7}}} \cdot \left (5 A c^{2} + C a c + C b^{2}\right ) - 384 a^{2} b^{4} c^{3} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{7}}} \cdot \left (5 A c^{2} + C a c + C b^{2}\right ) + 64 a b^{6} c^{2} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{7}}} \cdot \left (5 A c^{2} + C a c + C b^{2}\right ) - 4 b^{8} c \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{7}}} \cdot \left (5 A c^{2} + C a c + C b^{2}\right )}{40 A c^{4} + 8 C a c^{3} + 8 C b^{2} c^{2}} \right )} + 4 c \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{7}}} \cdot \left (5 A c^{2} + C a c + C b^{2}\right ) \log {\left (x + \frac {20 A b c^{3} + 4 C a b c^{2} + 4 C b^{3} c + 1024 a^{4} c^{5} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{7}}} \cdot \left (5 A c^{2} + C a c + C b^{2}\right ) - 1024 a^{3} b^{2} c^{4} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{7}}} \cdot \left (5 A c^{2} + C a c + C b^{2}\right ) + 384 a^{2} b^{4} c^{3} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{7}}} \cdot \left (5 A c^{2} + C a c + C b^{2}\right ) - 64 a b^{6} c^{2} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{7}}} \cdot \left (5 A c^{2} + C a c + C b^{2}\right ) + 4 b^{8} c \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{7}}} \cdot \left (5 A c^{2} + C a c + C b^{2}\right )}{40 A c^{4} + 8 C a c^{3} + 8 C b^{2} c^{2}} \right )} + \frac {66 A a^{2} b c^{2} - 13 A a b^{3} c + A b^{5} + 26 C a^{3} b c + C a^{2} b^{3} + x^{5} \cdot \left (60 A c^{5} + 12 C a c^{4} + 12 C b^{2} c^{3}\right ) + x^{4} \cdot \left (150 A b c^{4} + 30 C a b c^{3} + 30 C b^{3} c^{2}\right ) + x^{3} \cdot \left (160 A a c^{4} + 110 A b^{2} c^{3} + 32 C a^{2} c^{3} + 54 C a b^{2} c^{2} + 22 C b^{4} c\right ) + x^{2} \cdot \left (240 A a b c^{3} + 15 A b^{3} c^{2} + 48 C a^{2} b c^{2} + 51 C a b^{3} c + 3 C b^{5}\right ) + x \left (132 A a^{2} c^{3} + 54 A a b^{2} c^{2} - 3 A b^{4} c - 12 C a^{3} c^{2} + 66 C a^{2} b^{2} c + 3 C a b^{4}\right )}{192 a^{6} c^{3} - 144 a^{5} b^{2} c^{2} + 36 a^{4} b^{4} c - 3 a^{3} b^{6} + x^{6} \cdot \left (192 a^{3} c^{6} - 144 a^{2} b^{2} c^{5} + 36 a b^{4} c^{4} - 3 b^{6} c^{3}\right ) + x^{5} \cdot \left (576 a^{3} b c^{5} - 432 a^{2} b^{3} c^{4} + 108 a b^{5} c^{3} - 9 b^{7} c^{2}\right ) + x^{4} \cdot \left (576 a^{4} c^{5} + 144 a^{3} b^{2} c^{4} - 324 a^{2} b^{4} c^{3} + 99 a b^{6} c^{2} - 9 b^{8} c\right ) + x^{3} \cdot \left (1152 a^{4} b c^{4} - 672 a^{3} b^{3} c^{3} + 72 a^{2} b^{5} c^{2} + 18 a b^{7} c - 3 b^{9}\right ) + x^{2} \cdot \left (576 a^{5} c^{4} + 144 a^{4} b^{2} c^{3} - 324 a^{3} b^{4} c^{2} + 99 a^{2} b^{6} c - 9 a b^{8}\right ) + x \left (576 a^{5} b c^{3} - 432 a^{4} b^{3} c^{2} + 108 a^{3} b^{5} c - 9 a^{2} b^{7}\right )} \]

input
integrate((C*x**2+A)/(c*x**2+b*x+a)**4,x)
 
output
-4*c*sqrt(-1/(4*a*c - b**2)**7)*(5*A*c**2 + C*a*c + C*b**2)*log(x + (20*A* 
b*c**3 + 4*C*a*b*c**2 + 4*C*b**3*c - 1024*a**4*c**5*sqrt(-1/(4*a*c - b**2) 
**7)*(5*A*c**2 + C*a*c + C*b**2) + 1024*a**3*b**2*c**4*sqrt(-1/(4*a*c - b* 
*2)**7)*(5*A*c**2 + C*a*c + C*b**2) - 384*a**2*b**4*c**3*sqrt(-1/(4*a*c - 
b**2)**7)*(5*A*c**2 + C*a*c + C*b**2) + 64*a*b**6*c**2*sqrt(-1/(4*a*c - b* 
*2)**7)*(5*A*c**2 + C*a*c + C*b**2) - 4*b**8*c*sqrt(-1/(4*a*c - b**2)**7)* 
(5*A*c**2 + C*a*c + C*b**2))/(40*A*c**4 + 8*C*a*c**3 + 8*C*b**2*c**2)) + 4 
*c*sqrt(-1/(4*a*c - b**2)**7)*(5*A*c**2 + C*a*c + C*b**2)*log(x + (20*A*b* 
c**3 + 4*C*a*b*c**2 + 4*C*b**3*c + 1024*a**4*c**5*sqrt(-1/(4*a*c - b**2)** 
7)*(5*A*c**2 + C*a*c + C*b**2) - 1024*a**3*b**2*c**4*sqrt(-1/(4*a*c - b**2 
)**7)*(5*A*c**2 + C*a*c + C*b**2) + 384*a**2*b**4*c**3*sqrt(-1/(4*a*c - b* 
*2)**7)*(5*A*c**2 + C*a*c + C*b**2) - 64*a*b**6*c**2*sqrt(-1/(4*a*c - b**2 
)**7)*(5*A*c**2 + C*a*c + C*b**2) + 4*b**8*c*sqrt(-1/(4*a*c - b**2)**7)*(5 
*A*c**2 + C*a*c + C*b**2))/(40*A*c**4 + 8*C*a*c**3 + 8*C*b**2*c**2)) + (66 
*A*a**2*b*c**2 - 13*A*a*b**3*c + A*b**5 + 26*C*a**3*b*c + C*a**2*b**3 + x* 
*5*(60*A*c**5 + 12*C*a*c**4 + 12*C*b**2*c**3) + x**4*(150*A*b*c**4 + 30*C* 
a*b*c**3 + 30*C*b**3*c**2) + x**3*(160*A*a*c**4 + 110*A*b**2*c**3 + 32*C*a 
**2*c**3 + 54*C*a*b**2*c**2 + 22*C*b**4*c) + x**2*(240*A*a*b*c**3 + 15*A*b 
**3*c**2 + 48*C*a**2*b*c**2 + 51*C*a*b**3*c + 3*C*b**5) + x*(132*A*a**2*c* 
*3 + 54*A*a*b**2*c**2 - 3*A*b**4*c - 12*C*a**3*c**2 + 66*C*a**2*b**2*c ...
 
3.2.47.7 Maxima [F(-2)]

Exception generated. \[ \int \frac {A+C x^2}{\left (a+b x+c x^2\right )^4} \, dx=\text {Exception raised: ValueError} \]

input
integrate((C*x^2+A)/(c*x^2+b*x+a)^4,x, algorithm="maxima")
 
output
Exception raised: ValueError >> Computation failed since Maxima requested 
additional constraints; using the 'assume' command before evaluation *may* 
 help (example of legal syntax is 'assume(4*a*c-b^2>0)', see `assume?` for 
 more deta
 
3.2.47.8 Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 407 vs. \(2 (198) = 396\).

Time = 0.26 (sec) , antiderivative size = 407, normalized size of antiderivative = 1.98 \[ \int \frac {A+C x^2}{\left (a+b x+c x^2\right )^4} \, dx=-\frac {8 \, {\left (C b^{2} c + C a c^{2} + 5 \, A c^{3}\right )} \arctan \left (\frac {2 \, c x + b}{\sqrt {-b^{2} + 4 \, a c}}\right )}{{\left (b^{6} - 12 \, a b^{4} c + 48 \, a^{2} b^{2} c^{2} - 64 \, a^{3} c^{3}\right )} \sqrt {-b^{2} + 4 \, a c}} - \frac {12 \, C b^{2} c^{3} x^{5} + 12 \, C a c^{4} x^{5} + 60 \, A c^{5} x^{5} + 30 \, C b^{3} c^{2} x^{4} + 30 \, C a b c^{3} x^{4} + 150 \, A b c^{4} x^{4} + 22 \, C b^{4} c x^{3} + 54 \, C a b^{2} c^{2} x^{3} + 32 \, C a^{2} c^{3} x^{3} + 110 \, A b^{2} c^{3} x^{3} + 160 \, A a c^{4} x^{3} + 3 \, C b^{5} x^{2} + 51 \, C a b^{3} c x^{2} + 48 \, C a^{2} b c^{2} x^{2} + 15 \, A b^{3} c^{2} x^{2} + 240 \, A a b c^{3} x^{2} + 3 \, C a b^{4} x + 66 \, C a^{2} b^{2} c x - 3 \, A b^{4} c x - 12 \, C a^{3} c^{2} x + 54 \, A a b^{2} c^{2} x + 132 \, A a^{2} c^{3} x + C a^{2} b^{3} + A b^{5} + 26 \, C a^{3} b c - 13 \, A a b^{3} c + 66 \, A a^{2} b c^{2}}{3 \, {\left (b^{6} - 12 \, a b^{4} c + 48 \, a^{2} b^{2} c^{2} - 64 \, a^{3} c^{3}\right )} {\left (c x^{2} + b x + a\right )}^{3}} \]

input
integrate((C*x^2+A)/(c*x^2+b*x+a)^4,x, algorithm="giac")
 
output
-8*(C*b^2*c + C*a*c^2 + 5*A*c^3)*arctan((2*c*x + b)/sqrt(-b^2 + 4*a*c))/(( 
b^6 - 12*a*b^4*c + 48*a^2*b^2*c^2 - 64*a^3*c^3)*sqrt(-b^2 + 4*a*c)) - 1/3* 
(12*C*b^2*c^3*x^5 + 12*C*a*c^4*x^5 + 60*A*c^5*x^5 + 30*C*b^3*c^2*x^4 + 30* 
C*a*b*c^3*x^4 + 150*A*b*c^4*x^4 + 22*C*b^4*c*x^3 + 54*C*a*b^2*c^2*x^3 + 32 
*C*a^2*c^3*x^3 + 110*A*b^2*c^3*x^3 + 160*A*a*c^4*x^3 + 3*C*b^5*x^2 + 51*C* 
a*b^3*c*x^2 + 48*C*a^2*b*c^2*x^2 + 15*A*b^3*c^2*x^2 + 240*A*a*b*c^3*x^2 + 
3*C*a*b^4*x + 66*C*a^2*b^2*c*x - 3*A*b^4*c*x - 12*C*a^3*c^2*x + 54*A*a*b^2 
*c^2*x + 132*A*a^2*c^3*x + C*a^2*b^3 + A*b^5 + 26*C*a^3*b*c - 13*A*a*b^3*c 
 + 66*A*a^2*b*c^2)/((b^6 - 12*a*b^4*c + 48*a^2*b^2*c^2 - 64*a^3*c^3)*(c*x^ 
2 + b*x + a)^3)
 
3.2.47.9 Mupad [B] (verification not implemented)

Time = 13.25 (sec) , antiderivative size = 698, normalized size of antiderivative = 3.39 \[ \int \frac {A+C x^2}{\left (a+b x+c x^2\right )^4} \, dx=-\frac {\frac {26\,C\,a^3\,b\,c+C\,a^2\,b^3+66\,A\,a^2\,b\,c^2-13\,A\,a\,b^3\,c+A\,b^5}{3\,\left (-64\,a^3\,c^3+48\,a^2\,b^2\,c^2-12\,a\,b^4\,c+b^6\right )}+\frac {x\,\left (-4\,C\,a^3\,c^2+22\,C\,a^2\,b^2\,c+44\,A\,a^2\,c^3+C\,a\,b^4+18\,A\,a\,b^2\,c^2-A\,b^4\,c\right )}{-64\,a^3\,c^3+48\,a^2\,b^2\,c^2-12\,a\,b^4\,c+b^6}+\frac {2\,x^3\,\left (11\,b^2\,c+16\,a\,c^2\right )\,\left (C\,b^2+5\,A\,c^2+C\,a\,c\right )}{3\,\left (-64\,a^3\,c^3+48\,a^2\,b^2\,c^2-12\,a\,b^4\,c+b^6\right )}+\frac {x^2\,\left (b^3+16\,a\,c\,b\right )\,\left (C\,b^2+5\,A\,c^2+C\,a\,c\right )}{-64\,a^3\,c^3+48\,a^2\,b^2\,c^2-12\,a\,b^4\,c+b^6}+\frac {4\,c^3\,x^5\,\left (C\,b^2+5\,A\,c^2+C\,a\,c\right )}{-64\,a^3\,c^3+48\,a^2\,b^2\,c^2-12\,a\,b^4\,c+b^6}+\frac {10\,b\,c^2\,x^4\,\left (C\,b^2+5\,A\,c^2+C\,a\,c\right )}{-64\,a^3\,c^3+48\,a^2\,b^2\,c^2-12\,a\,b^4\,c+b^6}}{x^2\,\left (3\,c\,a^2+3\,a\,b^2\right )+x^4\,\left (3\,b^2\,c+3\,a\,c^2\right )+a^3+x^3\,\left (b^3+6\,a\,c\,b\right )+c^3\,x^6+3\,b\,c^2\,x^5+3\,a^2\,b\,x}-\frac {8\,c\,\mathrm {atan}\left (\frac {\left (\frac {8\,c^2\,x\,\left (C\,b^2+5\,A\,c^2+C\,a\,c\right )}{{\left (4\,a\,c-b^2\right )}^{7/2}}+\frac {4\,c\,\left (C\,b^2+5\,A\,c^2+C\,a\,c\right )\,\left (-64\,a^3\,b\,c^3+48\,a^2\,b^3\,c^2-12\,a\,b^5\,c+b^7\right )}{{\left (4\,a\,c-b^2\right )}^{7/2}\,\left (-64\,a^3\,c^3+48\,a^2\,b^2\,c^2-12\,a\,b^4\,c+b^6\right )}\right )\,\left (-64\,a^3\,c^3+48\,a^2\,b^2\,c^2-12\,a\,b^4\,c+b^6\right )}{4\,C\,b^2\,c+20\,A\,c^3+4\,C\,a\,c^2}\right )\,\left (C\,b^2+5\,A\,c^2+C\,a\,c\right )}{{\left (4\,a\,c-b^2\right )}^{7/2}} \]

input
int((A + C*x^2)/(a + b*x + c*x^2)^4,x)
 
output
- ((A*b^5 + C*a^2*b^3 - 13*A*a*b^3*c + 26*C*a^3*b*c + 66*A*a^2*b*c^2)/(3*( 
b^6 - 64*a^3*c^3 + 48*a^2*b^2*c^2 - 12*a*b^4*c)) + (x*(44*A*a^2*c^3 - 4*C* 
a^3*c^2 - A*b^4*c + C*a*b^4 + 18*A*a*b^2*c^2 + 22*C*a^2*b^2*c))/(b^6 - 64* 
a^3*c^3 + 48*a^2*b^2*c^2 - 12*a*b^4*c) + (2*x^3*(16*a*c^2 + 11*b^2*c)*(5*A 
*c^2 + C*b^2 + C*a*c))/(3*(b^6 - 64*a^3*c^3 + 48*a^2*b^2*c^2 - 12*a*b^4*c) 
) + (x^2*(b^3 + 16*a*b*c)*(5*A*c^2 + C*b^2 + C*a*c))/(b^6 - 64*a^3*c^3 + 4 
8*a^2*b^2*c^2 - 12*a*b^4*c) + (4*c^3*x^5*(5*A*c^2 + C*b^2 + C*a*c))/(b^6 - 
 64*a^3*c^3 + 48*a^2*b^2*c^2 - 12*a*b^4*c) + (10*b*c^2*x^4*(5*A*c^2 + C*b^ 
2 + C*a*c))/(b^6 - 64*a^3*c^3 + 48*a^2*b^2*c^2 - 12*a*b^4*c))/(x^2*(3*a*b^ 
2 + 3*a^2*c) + x^4*(3*a*c^2 + 3*b^2*c) + a^3 + x^3*(b^3 + 6*a*b*c) + c^3*x 
^6 + 3*b*c^2*x^5 + 3*a^2*b*x) - (8*c*atan((((8*c^2*x*(5*A*c^2 + C*b^2 + C* 
a*c))/(4*a*c - b^2)^(7/2) + (4*c*(5*A*c^2 + C*b^2 + C*a*c)*(b^7 - 64*a^3*b 
*c^3 + 48*a^2*b^3*c^2 - 12*a*b^5*c))/((4*a*c - b^2)^(7/2)*(b^6 - 64*a^3*c^ 
3 + 48*a^2*b^2*c^2 - 12*a*b^4*c)))*(b^6 - 64*a^3*c^3 + 48*a^2*b^2*c^2 - 12 
*a*b^4*c))/(20*A*c^3 + 4*C*a*c^2 + 4*C*b^2*c))*(5*A*c^2 + C*b^2 + C*a*c))/ 
(4*a*c - b^2)^(7/2)